SAT college Test
know all these formulas
http://www.mcelroytutoring.com/blog-post.php?id=281
http://www.allmathtricks.com/percentage-formulas/
Type 1 : General Percent formulas.
Find X is what percent on Y ?
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X is what percent greater than Yhttp://www.w3.org/1998/Math/MathML">
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Type 3 : Net percent change in area of circle or square
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If radius of a circle is decreased by http://www.w3.org/1998/Math/MathML">
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Examples for the above percentage formulas
Ex.1 : Find the net change in area of a circle , If radius of the circle decreases by http://www.w3.org/1998/Math/MathML">
Solution : – 20 + 10 – [(20 x 10) / 100)] = -10 – 2 = -12% ( i.e radius decreased by 12% so change in radius 1- 0.12 = 0.88)
Area = π x r2 = π x (0.88 r)2 = 0.7744 x π x r2
So Area of the circle decreased by 100- 77.44 = 22.56%
Ex.2 : Find the net change in area of a circle , If radius of the circle increases by http://www.w3.org/1998/Math/MathML">
Solution : 30 – 10 – [(30 x 10) / 100)] = 20 – 3 = -17% ( i.e radius increased by 17% so change in radius 1+0.17 = 1.17)
Area = π x r2 = π x (1.17 r)2 = 1.3689 x π x r2
So Area of the circle increased by 136.89 – 100 = 36.89%
Ex.3 : Find the net change in area of a square , If side of the square increases by http://www.w3.org/1998/Math/MathML">
Solution : (2 x 30) + (30 x 30 /100) = 60 + 9 = 69%
So Area of the square increased by 69%
Ex.4 : Find the net change in area of a circle , If radius of the circle decreases by http://www.w3.org/1998/Math/MathML">
Solution : – (2 x 18) + (18 x 18 /100) = – 36 +3.24 = – 32.73%.
So Area of the circle increased by 32.73%.
